Question 36
If $$x+(\frac{1}{x})=2$$, then what is the value of $$x^{21}+(\frac{1}{x^{1331}})$$ ?
Solution
Given : $$x+(\frac{1}{x})=2$$
=> $$\frac{x^2+1}{x}=2$$
=> $$x^2-2x+1=0$$
=> $$(x-1)^2=0$$
=> $$x=1$$
$$\therefore$$ $$x^{21}+(\frac{1}{x^{1331}})$$
= $$(1)^{21}+\frac{1}{(1)^{1331}}$$
= $$1+1=2$$
=> Ans - (C)
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