Question 36

If $$x+(\frac{1}{x})=2$$, then what is the value of $$x^{21}+(\frac{1}{x^{1331}})$$ ?

Solution

Given : $$x+(\frac{1}{x})=2$$

=> $$\frac{x^2+1}{x}=2$$

=> $$x^2-2x+1=0$$

=> $$(x-1)^2=0$$

=> $$x=1$$

$$\therefore$$ $$x^{21}+(\frac{1}{x^{1331}})$$

= $$(1)^{21}+\frac{1}{(1)^{1331}}$$

= $$1+1=2$$

=> Ans - (C)


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