Question 36

If the length of the side of an equilateral triangle is 8 cm, what is its area?

Solution

Side of equilateral triangle, $$s = 8$$ cm

Area of equilateral triangle = $$\frac{\sqrt{3}}{4} s^2$$

= $$\frac{\sqrt{3}}{4} \times (8)^2 = \sqrt{3} \times \frac{64}{4}$$

= $$16\sqrt{3}$$ sq. cm

=> Ans - (C)

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