Question 36

If A is coded as '$$+$$', B is coded as '$$\times$$', C is coded as '$$\div$$' and D is coded as '$$-$$', then

18 A 6 B 2 C 16 B 4 D 21 = ?

Solution

Given conditions :

A is coded as '$$+$$', B is coded as '$$\times$$', C is coded as '$$\div$$' and D is coded as '$$-$$'

Given Equation :

18 A 6 B 2 C 16 B 4 D 21

Equation After value putting : $$18+6\times\ 2\div16\times\ 4-21$$

Lets solve as per the rule of BODMAS :

$$18+3-21$$

= 0

Hence, Option C is correct.

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