Question 36
If A is coded as '$$+$$', B is coded as '$$\times$$', C is coded as '$$\div$$' and D is coded as '$$-$$', then
18 A 6 B 2 C 16 B 4 D 21 = ?
Solution
Given conditions :
A is coded as '$$+$$', B is coded as '$$\times$$', C is coded as '$$\div$$' and D is coded as '$$-$$'
Given Equation :
18 A 6 B 2 C 16 B 4 D 21
Equation After value putting : $$18+6\times\ 2\div16\times\ 4-21$$
Lets solve as per the rule of BODMAS :
$$18+3-21$$
= 0
Hence, Option C is correct.
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