Question 35
In the given figure, ABCD is a square of side 14 cm. E and F are mid points of sides AB and DC respectively. EPF is a semicircle whose diameter is EF. LMNO is a square. What is the area (in $$cm^2$$) of the shaded region?
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Solution
EF =14
Now area of square = 196
ARea of semi circle = $$\pi\ \times\ \frac{7^2}{2}=77$$
Now LN =7
so $$\sqrt{\ 2}s\ =7\ $$
we get s=$$\frac{7}{\sqrt{\ 2}}$$
so area of LMNO = s^2= $$\frac{49}{2}$$
Now area of shaded region = 196-77-24.5 = 94.5
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