Question 35

A rectangle with one side of length 4 cm is inscribed in a circle of diameter 5 cm . Find area of the rectangle

Solution

Given : AB = 4 cm and AC = 5 cm

To find : Area of rectangle ABCD = ?

Solution : In $$\triangle$$ ABC,

=> $$(BC)^2=(AC)^2-(AB)^2$$

=> $$(BC)^2=(5)^2-(4)^2$$

=> $$(BC)^2=25-16=9$$

=> $$BC=\sqrt{9}=3$$ cm

$$\therefore$$ Area of rectangle ABCD = $$AB \times BC$$

= $$4 \times 3=12$$ $$cm^2$$

=> Ans - (B)

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