A box contains 2 blue, 3 black and 4 red balls. Balls are drawn from the box at random one at a time without replacement. The probability of drawing 2 blue balls first followed by 3 black balls and subsequently 4 red balls is

A

$$\frac{2}{350}$$

B

$$\frac{1}{629}$$

C

$$\frac{1}{1260}$$

D

$$\frac{1}{24}$$