In a certain code the m“letter of the English alphabet is coded as the $$n^{th}$$ letter where n is the remainder obtained when 7m + 5 is divided by 26, $$1 \leq n \leq 26$$. For example, the third letter C becomes $$(7 \times 3 + 5) = 26^{th}$$ letter Z in the coded language. For decoding, the reverse process is followed. Based on this information, answer the questions.
Create a FREE account and get: