The emf of a cell corresponding to the reaction $$\text{Zn (s)} + 2\text{H}^+ \text{(aq)} \rightarrow \text{Zn}^{2+} (0.1 \text{ M}) + \text{H}_2 \text{(g)}$$ is 0.199 V at 298 K, where $$E^0_{\text{Zn}/\text{Zn}^{2+}} = 0.76 \text{ V}$$. The approximate pH of the solution at the electrode where hydrogen is being produced is ($$p_{\text{H}_2} = 1$$ atm)

A

8

B

9

C

10

D

11