In the given figure, in a right angle triangle $$ABC, AB = 12 cm$$ and $$AC = 15 cm$$. A square is inscribed in the triangle. One of the vertices of square coincides with the vertex of triangle. What is the maximum possible area (in $$cm^2$$) of the square?

A

$$\frac{1296}{49}$$

B

25

C

$$\frac{1225}{36}$$

D

$$\frac{1225}{64}$$