The minimum value of (x-2) (x-9) is
f(x) = (x-2)(x-9)
   = $$x^{2}$$-11x+18
f'(x) = 2x-11 = 0, x=11/2
f"(x)= 2 (positive) so f(x) has minimum value at x= 11/2
the minimum value is f(11/2) = -49/4.
so the answer is option D.
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