CAT 1996 Question Paper Question 31
In a mile race, Akshay can be given a start of 128 m by Bhairav. If Bhairav can give Chinmay a start of 4 m in a 100 m dash, then who out of Akshay and Chinmay will win a race of one and half miles, and what will be the final lead given by the winner to the loser? (One mile is 1,600 m.)
Akshay can complete 1600 - 128 = 1472 m and Bhairav can completer 1600 m in the same time.
Bhairav can complete 100 m and Chinmay can complete 96 m in the same time.
=> Bhairav can complete 1600 m and Chinmay can complete 1536 m in the same time.
=> Akshay can complete 1472 m and Chinmay can complete 1536 m in the same time.
1.5 miles => 2400 m
Distance travelled by Akshay by the time Chinmay completes 1.5 miles = $$\frac{1472}{1536}*2400$$ = 2300 m
=> Akshay lost by 100 m, which is $$\frac{1}{16}th$$ of a mile.
View Video Solution
Create a FREE account and get:
- All Quant CAT Formulas and shortcuts PDF
- 30+ CAT previous papers with solutions PDF
- Top 500 CAT Solved Questions for Free
