Solution
Given : $$x+y=4$$ -----------(i)
Cubing both sides, we get :
=> $$(x+y)^3=(4)^3$$
=> $$x^3+y^3+3xy(x+y)=64$$
=> $$x^3+y^3+3xy(4)=64$$
=> $$x^3+y^3+12xy=64$$
=> Ans - (C)
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