Question 31

Hospital is 12 km towards east of Rupin’s house. His school is 5 km towards south of Hospital. What is the shortest distance between Rupin’s house and school?

Solution

From the Pythagoras,

$$(AC)^2 = (AB)^2 + (BC)^2$$

$$(AC)^2 = (12)^2 + (5)^2$$

$$(AC)^2 = 169$$

AC = 13 km

Shortest distance = 13 km.

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