Four letter-cluster have been given out of which three are alike in some manner, while one is different. Choose the odd one.

 For that type of question solve by given option 

We check option( A ) B E H K 

We know that alphabet position A =1, B = 2, C =3 , D = 4 ........ and so on.

then  B =2 , E = 5 , H = 8 , K = 11

so  B E H K = 2 5 8 11  (Every alphabet position gap is 3)

same as we check option (B) G J M Q

then G = 7, J = 10 , M= 13, Q = 17

so G J M Q  = 7 10 13 17 (Every alphabet position gap not same)

Again we check same as option (C) M P S V

then M = 13 ,P= 16, S = 19, V = 22

so  M P S V = 13 16 19 22 ( Every alphabet position gap is 3)

Again we check same as option (D) R U X A

then R = 18, U = 21, X = 24 , A = 1

so  R U X A = 18 21 24 1 (Every alphabet position gap is 3)

from the above lines we can say  option B is different from A, C, D

so option B is right.