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Solution
For x<0 ; y=x+2
for 0<x<$$\frac{1}{2}$$ ; $$y=x+2$$
for $$x>\frac{1}{2}$$ ; $$y=3-x$$
Hence, $$y$$ attains its maxima at $$x=\frac{1}{2}$$ i.e. $$y$$ = 2.5
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