Question 30

In the given figure, $$AB$$ is a diameter of the circle with centre $$O$$ and $$XY$$ is the tangent at a point $$C$$. If $$\angle ACX = 35^\circ$$. then what is the value (in degrees) of $$\angle CAB$$?

Solution

We have :

Now Joining OC we get OCX =90
Therefore angle OCA =90-35 =55
Now in triangle AOC
OA=OC
so we get angle OCA=OAC =55
so angle CAB =55

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