Determine the value of $$\frac{x+y}{x+2y}$$ when $$\frac{2x+y}{x+4y}=3$$
Expression : $$\frac{2x+y}{x+4y}=3$$
=> $$2x+y=3x+12y$$
=> $$3x-2x=y-12y$$
=> $$x=-11y$$
$$\therefore$$Â $$\frac{x+y}{x+2y}$$
= $$\frac{-11y+y}{-11y+2y}$$
= $$\frac{-10y}{-9y}=\frac{10}{9}$$
=> Ans - (D)
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