In the adjoining figure, triangles $$\triangle ABD$$ and $$\triangle BCE$$ are equilateral triangles. The measure of $$\angle AFC$$ is ______ degrees.

Triangles $$ABE$$ and $$DBC$$ are congruent because $$AB=BD$$, $$BE=BC$$ and both included angles at $$B$$ are $$120^\circ$$. Let $$\angle AEB=\angle DCB=x$$. Then in triangle $$FEC$$, $$\angle FEC=60^\circ+x$$ and $$\angle FCE=60^\circ-x$$, so the exterior angle $$\angle AFC$$ equals their sum, which is $$120^\circ$$.