In a city, 40% of the people are illiterate and 60% are poor. Among the rich, 10% are illiterate. The percentage of the illiterate poor population is

Let total population of city = 100

Total number of illiterates = $$\frac{40}{100} \times 100=40$$

Number of poor people = $$\frac{60}{100} \times 100=60$$

=> Number of rich people = $$100-60=40$$

Now, number of rich who are illiterate = $$\frac{10}{100} \times 40=4$$

=> Remaining illiterates are poor = $$40-4=36$$

$$\therefore$$ Percentage of the illiterate poor population = $$\frac{36}{60} \times 100$$

= $$36 \times \frac{5}{3}=60\%$$

=> Ans - (B)