Question 29

If 6 A 11 B 33 = 18 and 4 B 18 A 9 = 8, then 3 A 5 B 35 = ?

Solution

Given : 6 A 11 B 33 = 18 and 4 B 18 A 9 = 8

If we replace, $$A=\div$$ and $$B=\times$$, we get the desired result.

Eg :- $$\frac{6}{11}\times33=6\times3=18$$

and $$4\times\frac{18}{9}=4\times2=8$$

Similarly, 3 A 5 B 35 = $$\frac{3}{5}\times35=3\times7=21$$

=> Ans - (C)

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