A large watermelon weighs $$20$$ kg with $$98\%$$ of its weight being water. It is left outside in the sunshine for some time. Some water evaporated and the water content in the watermelon is now $$95\%$$ of its weight in water. The reduced weight in kg is ------.
Correct Answer: 12
Solution
The non-water (solid) content is $$2\%$$ of $$20$$ kg, i.e. $$0.4$$ kg, and this stays constant. After evaporation the solid content is $$5\%$$ of the new weight, so the new weight is $$\frac{0.4}{0.05}=8$$ kg. The reduction in weight is $$20-8=12$$ kg.
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