What is the area (in sq cm) of an equilateral triangle of side 14 cm?
Side of equilateral triangle = $$a=14$$ cm
=> Area of equilateral triangle = $$\frac{\sqrt3}{4}a^2$$
= $$\frac{\sqrt3}{4}\times(14)^2$$
= $$\frac{196}{4}\sqrt3=49\sqrt3$$ $$cm^2$$
=> Ans - (A)
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