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The solution of differential equation $$\frac{dy}{dx} = e^{x - y} + x^{2} e^{-y}$$ is
$$e^{y} = e^{x} + \frac{x^{3}}{3} + c$$
$$e^{y} - e^{x} = c$$
$$x - e^{y} = c$$
$$e^{y} + e^{x} + \frac{x^{3}}{3} + y = 0$$
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