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If 11 @ 13 @ 7 = 13711 and 4 @ 14 @ 6 = 1464, then 12 @ 6 @ 13 = ?
The pattern followed is that the numbers are concatenated in such a way : a @ b @ c $$\equiv bca$$
Eg :- 11 @ 13 @ 7 = 13,7,11 $$\equiv13711$$
and 4 @ 14 @ 6 = 14,6,4 $$\equiv1464$$
Similarly, 12 @ 6 @ 13 = 6,13,12 $$\equiv61312$$
=> Ans - (C)
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