CAT 2004 Question Paper Question 28

Question 28

A circle with radius 2 is placed against a right angle. Another smaller circle is also placed as shown in the adjoining figure. What is the radius of the smaller circle?

Solution

Using pythagoras we can find diagonal of small square shown in fig. = 2*$$\sqrt2$$ . Now this is equal to 2 + r + $$\sqrt2$$ *r. Equating we get r = $$6- 4 \sqrt{2}$$

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Comments

Pavan Kumar

1 year, 7 months ago

Excellent way of approach. Brilliant

SAHIL KAUSHAL

2 years ago

that Was brilliant

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