Question 28

A circle with radius 2 is placed against a right angle. Another smaller circle is also placed as shown in the adjoining figure. What is the radius of the smaller circle?

Solution

Using pythagoras we can find diagonal of small square shown in fig. = 2*$$\sqrt2$$ . Now this is equal to 2 + r +  $$\sqrt2$$ *r. Equating we get r = $$6- 4 \sqrt{2}$$

Video Solution

video

Your Doubts




Ask a Doubt (know more)

Drop Your File Here!

** You can Drag and Drop an Image in the above textarea
add image

Create a FREE account and get:

  • All Quant CAT complete Formulas and shortcuts PDF
  • 38+ CAT previous year papers with video solutions PDF
  • 5000+ Topic-wise Previous year CAT Solved Questions for Free

Related Formulas With Tests

cracku

Boost your Prep!

Download App