Question 26

What least number must be added to 4131, so that the sum is completely divisible by 19?

Solution

Factorizing 4131 = 19 $$\times$$ 217 + 8

Thus, on dividing 4131 by 19, the remainder is 8

$$\therefore$$ The number that must be added to 4131 so that the sum obtained is completely divisible by 19

= 19 - 8 = 11

=> Ans - (B)

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