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Question 25
ΔABC is right angled at B. If $$sec A = \frac{5}{3}$$, then what is the value of $$cosec C$$ ?
Solution
Given : $$\sec A$$ = $$\frac{5}{3}$$
Also, $$\sec A=\frac{AC}{AB}=\frac{5}{3}$$
Let AC = 5 cm and AB = 3 cm
To find : $$\cosec C=\frac{AC}{AB}$$
= $$\frac{5}{3}$$
=> Ans - (A)
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