Question 25

ΔABC is right angled at B. If $$sec A = \frac{5}{3}$$, then what is the value of $$cosec C$$ ?

Solution

Given : $$\sec A$$ = $$\frac{5}{3}$$

Also, $$\sec A=\frac{AC}{AB}=\frac{5}{3}$$

Let AC = 5 cm and AB = 3 cm

To find : $$\cosec C=\frac{AC}{AB}$$

= $$\frac{5}{3}$$

=> Ans - (A)

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