When $$a = 2025$$, the numerical value of $$|2a^3-3a^2-2a+1| - |2a^3-3a^2-3a-2025|$$ is ------.

$$|2a^3-3a^2-2a+1| - |2a^3-3a^2-3a-2025|$$

or, $$|2a^3-3a^2-2a+1| - |2a^3-3a^2-3a-a|$$

or, $$|2a^3-3a^2-2a+1| - |2a^3-3a^2-4a|$$

Let us assume that $$t=2a^3-3a^2-2a$$

or, $$t=a(2a^2-3a-2)$$

or, $$t=a(2a+1)(a-2)$$

or, $$t=(2a+1)(a)(a-2)$$

Since, $$a=2025$$, we will get $$t>2a$$

Now, we have: $$|2a^3-3a^2-2a+1| - |2a^3-3a^2-4a|$$

Substituting value of $$t$$, we get:

$$|t+1|-|t-2a|$$

Since both of the quantities inside the modulus are positive

So, we get:

$$t+1-t+2a$$

$$=2a+1=4051$$