Question 24
ΔPQR is right angled at Q. If m$$\angle$$P = 60°, then find the value of $$(cot R + \frac{\sqrt{3}}{2})$$.
Solution
Sum of angles of $$\triangle$$ PQR = $$\angle P+\angle Q+\angle R=180^\circ$$
=> $$60^\circ+90^\circ+\angle R=180^\circ$$
=> $$\angle R=180^\circ-150^\circ=30^\circ$$
To find : $$(cot R + \frac{\sqrt{3}}{2})$$
= $$cot(30^\circ)+\frac{\sqrt3}{2}$$
= $$\sqrt3+\frac{\sqrt3}{2}$$
= $$\frac{3\sqrt3}{2}$$
=> Ans - (A)
Create a FREE account and get:
- Free SSC Study Material - 18000 Questions
- 230+ SSC previous papers with solutions PDF
- 100+ SSC Online Tests for Free
CAT Quant Questions | CAT Quantitative Ability
CAT Averages Mixtures Alligations QuestionsCAT Quadratic Equations QuestionsCAT Linear Equations QuestionsCAT Algebra QuestionsCAT Time, Distance and Work Questions
CAT DILR Questions | LRDI Questions For CAT
CAT Maxima-Minima QuestionsCAT Coins and Weights QuestionsCAT Quant Based DI QuestionsCAT Data change over a period QuestionsCAT Routes And Networks Questions
