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Question 24
In a triangle $$PQR$$, $$\angle PQR = 90$$°, $$PQ$$ = 10 cm and $$PR$$ = 26 cm, then what is the value (in cm) of inradius of incircle?
Solution
We know area of a triangle=r*s
it is a right angled triangle and phytogerean triplet of 5,12,13 i.e 10,24 and 26
So given two sides are 10 and 26 and so third side is 24
Area of the triangle=(1/2)bh
(1/2)*24*10
=120 sq cm
S=(a+b+c)/2
=60/2
=30
Therefore r=120/30
=4 cm
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