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126 g oxalic acid ($$\text{H}_2\text{C}_2\text{O}_4 \cdot 2\text{H}_2\text{O}$$) under acidic conditions will be oxidized by
(i) $$\frac{1}{3}$$ mole of $$\text{K}_2\text{Cr}_2\text{O}_7$$
(ii) $$\frac{5}{2}$$ mol $$\text{K}_2\text{Cr}_2\text{O}_7$$
(iii) $$\frac{1}{3}$$ mol $$\text{KMnO}_4$$
(iv) $$\frac{5}{2}$$ mol $$\text{KMnO}_4$$
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