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Question 23
In triangle $$PQR$$, the internal bisector of $$\angle Q$$ and $$\angle R$$ meets at O. If $$\angle QPR$$ = 70°, then what is the value (in degrees) of $$\angle QOR$$?
Solution
So,
$$\angle QOR=90^{\circ\ }+\frac{70^{\circ\ }}{2}=125^{\circ\ }.$$
So, B is correct choice.
we know that,
If Bisectors of angle Q and angle R of triangle PQR meet at point O. then, angle QOR = 90°+1⁄2 angle P
So,
$$\angle QOR=90^{\circ\ }+\frac{70^{\circ\ }}{2}=125^{\circ\ }.$$
So, B is correct choice.
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