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Question 23
A was twice as old as B, two years ago. If the difference in their ages be 2 years, find A’ s age.
Solution
Let B's age two years ago = $$x$$ years
=> A's age 2 years ago = $$2x$$ years
=> Difference in age (remains constant) = $$2x-x=2$$
=> $$x=2$$
$$\therefore$$ A's present age = $$2(2)+2=6$$ years
=> Ans - (D)
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