Let radius of semi circle = $$r$$ cm
Area = $$\frac{\pi r^2}{2}=308$$
=> $$\frac{22}{7}\times\frac{1}{2}\times r^2=308$$
=> $$r^2=308\times\frac{7}{11}=196$$
=> $$r=\sqrt{196}=14$$ cm
$$\therefore$$ Perimeter of semi circle = $$\pi r+2r$$
= $$(\frac{22}{7}\times14)+(2\times14)$$
= $$44+28=72$$ cm
=> Ans - (D)
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