If $$x + 3y - \frac{2z}{4} = 6, x + \frac{2}{3}(2y + 3z) = 33$$ and $$\frac{1}{7}(x + y + z) + 2z = 9$$, then what is the value of $$46x +131y$$

A

414

B

364

C

384

D

464