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If $$a = \sqrt{(2025)^3 - (2023)^3}$$, the value of $$\sqrt{\frac{a^2-2}{6}}$$ is ------.
Correct Answer: 2024
Since $$a^2 = 2025^3-2023^3 = (2024+1)^3-(2024-1)^3$$
$$a^2=2024^2+1+3*2024+3*(2024)^2-[2024^2-1+3*(2024)-3*(2024)^2]$$
$$a^2=6*(2024)^2+2$$
$$a^2-2=6*(2024)^2$$
$$\dfrac{a^2-2}{6}=2024^2$$
$$\sqrt{\dfrac{a^2-2}{6}}=2024$$
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