Question 21

The side of an equilateral triangle is 8 cm. Find its area (in cm)

Solution

Side of equilateral triangle = $$s=8$$ cm

=> Area = $$\frac{\sqrt3}{4} s^2$$

= $$\frac{\sqrt3}{4}\times(8)^2$$

= $$\sqrt3\times16=16\sqrt3$$ $$cm^2$$

=> Ans - (D)

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