Question 21

The side of an equilateral triangle is 14 cm. Find its area in $$cm^{2}$$

Solution

Side of equilateral triangle = $$s=14$$ cm

=> Area = $$\frac{\sqrt3}{4} s^2$$

= $$\frac{\sqrt3}{4}\times(14)^2$$

= $$\sqrt3\times7\times7=49\sqrt3$$ $$cm^2$$

=> Ans - (D)


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