The side of an equilateral triangle is 14 cm. Find its area in $$cm^{2}$$
Side of equilateral triangle = $$s=14$$ cm
=> Area = $$\frac{\sqrt3}{4} s^2$$
= $$\frac{\sqrt3}{4}\times(14)^2$$
= $$\sqrt3\times7\times7=49\sqrt3$$ $$cm^2$$
=> Ans - (D)
Create a FREE account and get:
