Question 21

The side of an equilateral triangle is 10 cm. Find its area $$(in cm^2)$$

Solution

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Side of equilateral triangle = 10 cm

Area of equilateral triangle = $$\frac{\sqrt3}{4} (s)^2$$

= $$\frac{\sqrt3}{4}\times(10)^2$$

= $$25\sqrt3$$ $$cm^2$$

=> Ans - (A)

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