The side of an equilateral triangle is 10 cm. Find its area $$(in cm^2)$$
Side of equilateral triangle = 10 cm
Area of equilateral triangle = $$\frac{\sqrt3}{4} (s)^2$$
=Â $$\frac{\sqrt3}{4}\times(10)^2$$
= $$25\sqrt3$$ $$cm^2$$
=> Ans - (A)
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