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Question 21
If $$x - 4y = 0$$ and $$x + 2y = 24$$, then what is the value of $$\frac{(2x + 3y)}{(2x - 3y)}$$?
Solution
Given x-4y=0
x=4y
x+2y=24
6y=24
y=4
x=16
$$\frac{(2x + 3y)}{(2x - 3y)}$$=$$\frac{(2*(16) + 3*(4))}{(2*(16) - 3*(4))}$$
=44/20
=11/5
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