If the lengths of the two parallel sides of a trapezium are 7 cm and 9 cm and its area is 80 cm2. Find the distance between its parallel sides (in cm).
Let distance between parallel sides = height of trapezium =Â $$h$$ cm
=> Sum of lengths of parallel sides = $$7+9=16$$ cm
=> Area of trapezium = $$\frac{1}{2} \times$$ (sum of parallel sides) $$\times$$ height
=> $$\frac{1}{2}\times16\times h=80$$
=> $$h=\frac{80}{8}=10$$ cm
=> Ans - (B)
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