A rectangular box of width(a), length(b), and height(c) has a solid cylinder of height 'c' and of diameter 'a' placed within it. If a= 6, b =8 and c =10, how much volume is left in the rectangular box ?

Volume left out in the rectangular box = Total volume of the rectangular box - Volume of the cylinder placed within it.

Total volume of the rectangular box of width(a), length(b), and height(c) is given as (V) = $$a\times b\times c$$ cubic units.

= $$6\times 8\times 10$$

= 480 cubic units.

Volume of the solid cylinder of height 'c' and of diameter 'a' is given by (V') = $$\frac{\pi}{4}*a^2*c$$ cubic units.

= $$\frac{\pi}{4} * 6^2 * 10$$

= 90$$\pi$$ cubic units.

Therefore left out volume = 480 - 90$$\pi$$ cubic units.