Which two numbers, from amongst the given options, should be interchanged to make the given equation correct?
$$\left(6\right)^{3} \div 12 + \left[\left(\sqrt{81}\right) \times 4\right] - \left(28 \div 2\right) + 24 = 43$$

A

12 and 24

B

6 and 24

C

81 and 4

D

28 and 24