Question 20

When a heap of pebbles is grouped in 32, 40 or 72 it is left with remainders of 10,
18 or 50 respectively. What is the minimum number of pebbles that the heap contains?

Solution

Family of numbers when divided by a,b,c and leaves remainders x,y,z respectively such that (a-x)=(b-y)=(c-z)=v are of the form N = k *LCM ( a,b,c) - v

Therefore N = k*LCM(32,40,72) - 22 => N=1440k-22

Smallest such number is obtained when k=1 which is 1418

View More Questions From Number Systems

Create a FREE account and get:

All Quant Formulas and shortcuts PDF
200+ previous papers with solutions PDF
Top 5000+ MBA exam Solved Questions for Free

SNAP Quant Questions | SNAP Quantitative Ability

SNAP Profit and Loss Questions SNAP Inequalities Questions SNAP Functions, Graphs and Statistics Questions SNAP Geometry Questions SNAP Data Sufficiency Questions

SNAP DILR Questions | LRDI Questions For SNAP

SNAP Data Interpretation Questions SNAP Logical Reasoning Questions

SNAP Verbal Ability Questions | VARC Questions For SNAP

SNAP Vocabulary Questions SNAP Reading Comprehension Questions SNAP Grammar and Sentence Correction Questions SNAP Para Summary Questions SNAP Para Jumbles Questions

Free SNAP Quant Questions

SNAP Number Systems

SNAP Profit and Loss

SNAP Inequalities

SNAP Logarithms, Surds and Indices

SNAP Venn Diagrams

SNAP Progressions and Series

SNAP Time, Speed and Distance

SNAP Probability, Combinatorics

SNAP Data Sufficiency

SNAP Geometry

SNAP Quadratic Equations

SNAP Linear Equations

SNAP Averages, Ratio and Proportion

SNAP Functions, Graphs and Statistics

When a heap of pebbles is grouped in 32, 40 or 72 it is left with remainders of 10,18 or 50 respectively. What is the minimum number of pebbles that the heap contains?