Question 19

P is six times as large as Q. By what per cent is Q less than P?

Solution

Given P =6Q

Required answer is

$$\ \frac{\ P-Q}{P}\times\ 100$$%

= $$\ \frac{\ 5Q}{6Q}\times\ 100$$% (since P=6Q)

= $$83\frac{\ 1}{3}$$ %

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