The figure shows three circuits I, II and III which are connected to a 3 V battery. If the powers dissipated by the configurations I, II and III are $$P_1$$, $$P_2$$ and $$P_3$$ respectively, then -

The configuration (I) is a balanced wheatstone bridge with an effective resistance of $$R_{e1}=\frac{\left(1+1\right)\cdot\left(1+1\right)}{\left(1+1\right)+\left(1+1\right)}=\frac{4}{4}=1Ω$$

Power, $$P_1=\frac{V^2}{R_{e1}}=\frac{9}{1}=9\ W$$

Effective resistance of configuration (II) is $$R_{e2}=\frac{1\cdot1}{1+1}=0.5Ω$$

Power, $$P_2=\frac{V^2}{R_{e2}}=\frac{9}{0.5}=18\ W$$

Effective resistance of configuration (III) is $$R_{e3}=1+\frac{2\cdot2}{2+2}=2Ω$$

Power, $$P_3=\frac{V^2}{R_{e3}}=\frac{9}{2}=4.5\ W$$

$$\therefore\ $$ $$P_2>P_1>P_3$$