Consider a parallel plate capacitor. When half of the space between the plates is filled with some dielectric material of dielectric constant $$K$$ as shown in Fig. (1) below, the capacitance is $$C_1$$. However, if the same dielectric material fills half the space as shown in Fig. (2), the capacitance is $$C_2$$. Therefore, the ratio $$C_1 \colon C_2$$ is

A

1

B

$$\frac{2K}{K+1}$$

C

$$\frac{4K}{(K+1)^2}$$

D

$$\frac{K+1}{2}$$