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A three stage Johnson counter ring in figure is clocked at a constant frequency of $$f_c$$. from starting state of $$Q_0, Q_1, Q_2 = 101$$. The frequencyof output $$Q_0, Q_1, Q_2,$$ will be
$$\frac{f_c}{2}$$
$$\frac{f_c}{6}$$
$$\frac{f_c}{3}$$
$$\frac{f_c}{8}$$
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