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Question 20

A particle of charge $$16 \times 10^{-16}$$ C moving with velocity 10 ms$$^{-1}$$ along x-axis enters a region where magnetic field of induction $$\vec{B}$$ is along the y-axis and an electric field of magnitude $$10^4$$ Vm$$^{-1}$$ is along the negative z-axis. If the charged particle continues moving along x-axis, the magnitude of $$\vec{B}$$ is :

$$\vec{F}_{net} = q(\vec{E} + \vec{v} \times \vec{B}) = 0$$

$$qE = qvB$$

$$B = \frac{E}{v}$$

$$B = \frac{10^4}{10}$$

$$B = 10^3\text{ Wb m}^{-2}$$

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