Solution
Let the three consecutive odd numbers be $$(x-2),(x),(x+2)$$
According to ques,
=> $$(x-2)^2+(x)^2+(x+2)^2=2195$$
=> $$(x^2-4x+4)+(x^2)+(x^2+4x+4)=2195$$
=> $$3x^2+8=2195$$
=> $$3x^2=2195-8=2187$$
=> $$x^2=\frac{2187}{3}=729$$
=> $$x=\sqrt{729}=27$$
$$\therefore$$ Consecutive odd numbers are = $$25,27,29$$
=> Ans - (C)
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